4x^2-104x+100=0

Solution for 4x^2-104x+100=0 equation:

4x^2-104x+100=0

a = 4; b = -104; c = +100;
Δ = b2-4ac
Δ = -1042-4·4·100
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-96}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+96}{2*4}=\frac{200}{8}
=25
$